Question
If x, y and z are real numbers such that
(x-5)2+(y-7)2+(z-9)2= 0 then (x+y+z) is equal toSolution
if a2+b2+c2 +...so on = 0 then a=b=c=....so on = 0 So ATQ, x - 5 = 0, y - 7 = 0 and z - 9 = 0 So x=5, y =7 and z= 9 hence x + y + z = 5 + 7 + 9 = 21
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