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    Question

    If p = 27 - q - r and pq + r(q + p) = 168, then find

    the value of (p┬▓ + q┬▓ + r┬▓).
    A 381 Correct Answer Incorrect Answer
    B 387 Correct Answer Incorrect Answer
    C 393 Correct Answer Incorrect Answer
    D 399 Correct Answer Incorrect Answer

    Solution

    We have, p = 27 - q - r So, p + q + r = 27 And, pq + r(q + p) = 168 Or, pq + qr + pr = 168 Using, (p + q + r)┬▓ = p┬▓ + q┬▓ + r┬▓ + 2(pq + qr + pr) So, 27┬▓ = (p┬▓ + q┬▓ + r┬▓) + 2 ├Ч 168 Or, 729 = (p┬▓ + q┬▓ + r┬▓) + 336 Or, p┬▓ + q┬▓ + r┬▓ = 729 - 336 Or, p┬▓ + q┬▓ + r┬▓ = 393

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