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    Question

    If 27x3 - 8y3 = (3x - Ay) X

    (Bx2 + 4y2 + Cxy), then find the value of 3 X (2A + 6B) - 2C.
    A 162 Correct Answer Incorrect Answer
    B 148 Correct Answer Incorrect Answer
    C 174 Correct Answer Incorrect Answer
    D 156 Correct Answer Incorrect Answer

    Solution

    27x3 - 8y3 = (3x - Ay) X (Bx2 + 4y2 + Cxy) We know that, a3 - b3 = (a - b) X (a2 + b2 + ab) So, 27x3 - 8y3 = (3x)3 - (2y)3 = (3x - 2y) X (9x2 + 4y2 + 3x X 2y) = (3x - 2y) X (9x2 + 4y2 + 6xy) So, (3x - Ay) X (Bx2 + 4y2 + Cxy) = (3x - 2y) X (9x2 + 4y2 + 6xy) On comparing coefficients of LHS and RHS, we get, A = 2, B = 9, and C = 6 So, 3 X (2A + 6B) - 2C = 3 X {2 X 2 + 6 X 9} - 2 X 6 = 3 X (4 + 54) - 12 = 3 X 58 - 12 = 174 - 12 = 162

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