Question
If cos(A - B) = √3/2 and cot(A + B) = 1/√3,
where A - B and A + B are acute angles, then (2A - 3B) is equal to:Solution
cos(A - B) = √ 3/2 A – B = 30Ëš ---- (i) A + B = 60Ëš ---- (ii) Solving (i) and (ii) we get, => A = 45Ëš and B = 15Ëš Now, => tan (2A – 3B) = 90Ëš – 45Ëš = 45Ëš
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