Question
(a + 7)2 + (b – 2) 2 + (c +
3) 2 = 0, then find the value of 3a - 2b + c.Solution
If (a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then (a = -7), (b = 2), and (c = -3).
So,
- a + 7 = 0 → a = -7
- b - 2 = 0 → b = 2
- c + 3 = 0 → c = -3
Therefore, required value:
3(-7) - 2(2) + (-3) = -21 - 4 - 3 = -28
I. 6x² - 23x + 7 = 0
II. 6y² - 29y + 9 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
I. 4x² - 21 x + 20 = 0
II. 8y² - 22 y + 15 = 0
For 3x² − 10x − 8 = 0, find (1/α + 1/β).
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
If x and y satisfy x² + y² = 25 and x + y = 7, find xy.
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
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