Question
(a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then find the value of 3a - 2b +
c.
Solution
If (a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then (a = -7), (b = 2), and (c = -3).
So,
- a + 7 = 0 → a = -7
- b - 2 = 0 → b = 2
- c + 3 = 0 → c = -3
Therefore, required value:
3(-7) - 2(2) + (-3) = -21 - 4 - 3 = -28
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