Question
(a + 7)2 + (b – 2) 2 + (c +
3) 2 = 0, then find the value of 3a - 2b + c.Solution
If (a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then (a = -7), (b = 2), and (c = -3).
So,
- a + 7 = 0 → a = -7
- b - 2 = 0 → b = 2
- c + 3 = 0 → c = -3
Therefore, required value:
3(-7) - 2(2) + (-3) = -21 - 4 - 3 = -28
More Algebra Questions
(9.013 – 15.04) = ? + 9.98% of 5399.98
784.69 + 86.96 ÷ 29.01 = 40.01 + ? + 367.88
3.55% of 8120 – 66.66% of 540 = ? – 28% of 5500
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
647.1 ÷ ? + 72.3 × 209.81 – 8743.1 = 6404
3, 4, 10, 33, 136, ?
? = 25.08 + 11.99 × 24.07
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99
