Question
If x ,y,z are three integers such that x +y = 8,y +z =13
and z +x =17,then the value of x2 /yz  is:Solution
x + y = 8 ----(1)  y + z = 13 ----(2) z + x = 17 ----(3) Eq (1) + (2) + (3), 2(x + y + z) = 8 + 13 + 17  x + y + z = 38/2 = 19 ----(4) From eq (3) and (4),  x + 13 = 19 x = 6 From eq(3), z + x = 17 z + 6 = 17 z = 11 From eq(2), y + z = 13  y + 11 = 13  y = 2 x2/yz = 62 / 2×11 =36 / 22=18/11
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 154Â Â Â Â 165Â Â Â Â 143Â Â Â Â 175Â Â Â Â Â 132Â Â Â Â Â 187
...5000, 4500, 3600, 2480, 1512, 756Â Â Â
Find the wrong number in the given number series,
125, 150, 250, 475, 875, 1500
- Find the wrong number in the given number series.
5, 8, 12, 19, 27, 39 768Â Â Â 2304Â Â Â 288Â Â Â 864Â Â Â 106Â Â Â 324
Find the wrong number in the given number series.
5, 6, 14, 45, 188, 925
120, 240, 80, 320, 60, 384
21 32 54 86 131 186
... 7    12     33    126    635  Â
Relevant for Exams:
