Anil is 12 years older than Sunil. The ratio of Anil’s age 4 years ago to Sunil’s age 2 years hence is 31 : 25. Find the average of their present ages.

ATQ, Let Anil’s present age be x years. Anil is 12 years older than Sunil. So, Sunil’s present age = x − 12. Anil’s age 4 years ago = x − 4. Sunil’s age 2 years hence = x − 12 + 2 = x − 10. According to the question: (Anil’s age 4 years ago) : (Sunil’s age 2 years hence) = 31 : 25 So, (x − 4) : (x − 10) = 31 : 25 Now cross multiply. 25(x − 4) = 31(x − 10) 25x − 100 = 31x − 310 Bring x terms to one side and numbers to the other side. 31x − 25x = 310 − 100 6x = 210 x = 210/6 x = 35 So, Anil’s present age = 35 years Sunil’s present age = 35 − 12 = 23 years Now find the average of their present ages. Average = (35 + 23)/2 Average = 58/2 Average = 29 years