Question
Present ages of 'A' and 'B' are in the ratio 3:4, respectively. Present age of 'C' is 25% more than that of 'B'. If six years ago from now, the age of 'A' was 50% less than that of 'C', then find the present age of 'C'.
Solution
Let the present ages of 'A' and 'B' be '3x' years and '4x' years.
So, present ages of 'C' = 4x X 1.25 = '5x' years
ATQ;
(5x - 6) X 0.5 = (3x - 6)
Or, 2.5x - 3 = 3x - 6
Or, 0.5x = 3
So, x = 6
So, present age of 'C' = 6 X 5 = 30 years
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