Question
A is 3 years older than B while C is 5 years younger
than B. The ratio of age of A, 6 years hence and age of B, 5 years ago is 4:3. What was age of C, 8 years ago?Solution
Let the present age of B be x years. A’s present age = (x + 3) years C’s present age = (x - 5) years According to question, => [(x + 3) + 6]/(x -5) = 4/3 => x = 47 C’s age, 8 years ago = (47 - 5) – 8 = 34 years
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