Question
The ratio of age of ‘A’ 6 years ago to the age of ‘B’ 4 years hence from now is 2 : 3. If the sum of their present ages is 48 years, then find the age of ‘B’ 2 years ago from now.
Solution
Let the present ages of ‘A’ and ‘B’ be ‘p’ years and ‘q’ years respectively. Then,
p + q = 48 Or,
q = 48 − p ATQ, [{(p - 6)}/{(q + 4)} = {2/3}] Or,
3(p − 6) = 2(q + 4) Or,
3p − 18 = 2q + 8 Or,
3p − 2q = 26 Or,
3p − 2(48 − p) = 26 Or,
3p − 96 + 2p = 26 Or,
5p = 122 Or,
p = 24 Or,
q = 48 − 24 = 24 Therefore, age of ‘B’ 2 years ago from now = 24 − 2 = 22 years
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