Question
The present age ratio of a father to his son is 15:7,
and that of a mother to her daughter is 6:2. The mother is three years younger than the father, and the daughter is four years younger than the son. Find the mother’s age 10 years from now.Solution
Let present age of father and son be 15m and 7m years respectively, and mother and daughter be 6n and 2n years respectively. Now, 15m - 6n = 3 ------------ (I) 7m - 2n = 4 ------------- (II) Now solving I - 3 × II: 15m - 6n - 3(7m - 2n) = 3 - 12 15m - 6n - 21m + 6n = -9 -6m = -9 m = 1.5 Put in equation II: 7 × 1.5 - 2n = 4 10.5 - 2n = 4 2n = 6.5 n = 3.25 Required age = 6 × 3.25 + 10 = 29.5 years
47.87% of 749.76 + 35.11% of 399.76 = √? + 23.15 × 20.87
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(?)2 = (5.99)2 + (7.88)2 + 43.99
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What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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