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ATQ, Let age of Abhishek and Bheema, 12 years ago was 4x years and 5x years respectively. Present age of Chintu = 33 × 2 – (5x + 12) = (54 – 5x) years ATQ, (54 – 5x)/(4x + 12) = 2/3 Or, 162 – 15x = 8x + 24 Or, 23x = 138 Or, x = 6 So, present age of Bheema = 5 × 6 + 12 = 42 years Present age of Chintu = 54 – 5 × 6 = 24 years Desired ratio = 42:24 = 7:4
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69,012 ___Â 20,167 ___Â 51,246 ___Â 6 ___Â 50,000 = 7,386
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3,000 ___ 15 ___ 4 ___ (20)² ___ 20 = 32,200
The smallest fraction, which should be added to the sum of2(1/2), 3(1/3), 4(1/4) and 5(1/5) to make the result a whole number, is
`2/5` ___Â 15 ___Â 115___ 20 ___Â 4 = 581
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