Question
A 15-member group has two individuals aged 18 and 23.
When excluded, the average age of the rest increases by 3 years. Find the average age of all members.Solution
ATQ, Average age 'u' years. Total age 15u. Sum age 18+23=41. Remaining 15u−41. New average u+3. Equation: 15u−41=13(u+3) Solve: 15u−13u=41+39 ⇒80⇒2u=80 ⇒u=40
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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