Question
Present average age of 4 friends: ‘A’, ‘B’, ‘C’ and ‘D’ is 36 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years older than ‘B’, then find the sum of present ages of ‘A’ and ‘C’.
More Age Questions
- The ratio of the present ages of father and his son is 9:4. The product of their ages 3 years ago was 24 times of his son’s age that year. What was son’s a...
- Present ages of 'Amit' and 'Bishnu' are in the ratio 4:5, respectively. If seven years hence from now, the ratio of ages of 'Amit' and 'Bishnu' will be 5:6...
- The current age of 'P' is 40% more than the current age of 'Q'. Seven years from now, the ratio of their ages will be 14:11. What was the age of 'P' 3 year...
- There are 5 children in a family. The average age of the children is 10 years. If the present age of their mother and father is added, the average age of t...
- The present age of A is 3 times the age of B. Eight years ago, the ratio of their ages was 5 : 1. Find B's present age.
- Question 6
- Three years from now, the combined age of Aman and Bittu will be 42 years. Eight years ago, Aman was six years younger than Bittu. What will be Bittu’s age...
- Ratio of present age of 'A' to that of 'B' is 3:5. If the age of 'A' four years ago was 11 years, then after how many years, the ratio of the age of 'B' to...
- B is 4 years older than A and A is 8 years older than C. If the sum of the age of A and C is 22 years, then find the sum of the ages of all three.
- The present age of P is 40% more than that of Q, and the ratio of Q’s age to R’s age is 3:5. Find Q’s age 6 years ago if the oldest among them is 90 years ...
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