Question
Meena was married 6 years ago. At present her age is 5/4
times of her age at the time of her marriage. Her son’s age is 1/3 times of her present age. Find the present age of her son.Solution
Let the age of Meena at the time of her marriage be 4x. So, her present age = 5/4 × 4x = 5x According to question, => 4x = 5x – 6 => x = 6 Meena’s present age = 5x = 5 × 6 = 30 yrs Therefore, her son’s present age = (1/3) × 30 = 10 years
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