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      Question

      The present age of A is 7/5 times to that of his

      marriage age. Present age of his brother is 1/2nd of his present age. If A was married 20 years ago then find the present age of his brother.
      A 35 years Correct Answer Incorrect Answer
      B 16 years Correct Answer Incorrect Answer
      C 20 years Correct Answer Incorrect Answer
      D 12 years Correct Answer Incorrect Answer

      Solution

      Let the age of A when he was married be x years. Present age of A = 7x/5 Present age of his brother = (1/2)Β Γ—Β (7x/5) = 7x/10 According to Question, => x + 20 = 7/5x => 2/5x = 20 => x = 50 years Present age of his brother = (7/10) Γ—Β 50 = 35 years

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