Question
The present age of A is 7/4 times to that of his
marriage age. Present age of his brother is 1/2 of his present age. If A was married 18 years ago then find the present age of his brother.Solution
Let the age of A when he was married be x years. Present age of A = 7x/4 Present age of his brother = (1/2) × (7x/4) = 7x/8 According to Question, => x + 18 = 7/4x => 3/4x = 18 => x = 24 years Present age of his brother = (7/8) × 24 = 21 years
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