Question
Who was India's first female judge at the Supreme Court?
Solution
Justice M. Fathima Beevi made history in 1989 by becoming the first female judge of the Supreme Court of India, paving the way for more women in the highest judicial positions in the country.
If x = (2+√3)/(2-√3), y = (2-√3)/(2+√3)
Then find out the value of (x²+y²-xy)/(x²+y²+xy)
 `sqrt(sqrt(17+sqrt(17+sqrt(17)) ... prop)`  = ?
If (2a + b)/(3b - 2b) = 13/2 then 'b' is what percent of 'a'?
If x2 – 10x + 20 = 0, then find the value of (x – 3)2 + 1/(x – 3)2
The coefficient of ‘b2’ in (3a + b)3 is
If (a2 + 1/a2) = 18, then find the value of (a3 - 1/a3).
What is the value of (a² + b²+4c²- ab-2bc-2ca) (a + b+2c):
√4096 + √(?) + 13 – 29 = 148Â
 `sqrt(sqrt(10-sqrt(10-sqrt(10)) ... prop)` = ?
- If (a 2  + 1/a 2 ) = 66, then find the value of (a 3  – 1/a 3 ).