Question
A man borrowed Rs 200 and promised to pay back in 11
equal instalments of Rs 20 each. Find the rate of simple interest per annum?Solution
First month = Rs 200 Second month = Rs 180 Third month =Rs 160 Sum = n/2 {2a + ( n – 1 )d] a = 200  d = - 20 = (11/2) [2 x 200 + ( 11 – 1 ) (-20)]  = (11/2) [400 – 20]  = (11/2) x 200 = 1100  P = (200 x 11)/2 = 1,100  (P x R x T)/100 = S.I  (1100 x R x 1)/(100 x 12) = 20 R = (12 x 20)/11 = 21(9/11) %
12, 10, 23, 65, 265, 1289Â
Find the wrong number in the given number series, If wrong term is 'p', then find the value of √(p - 17) .
1195, 1172, 1143, 1106, 1075, 10...
Find the wrong number in given number series.
3230, 3198, 3090, 2083, 2334, 1430.
Find the wrong number in the given number series.
256, 64, 16, 4, 2, 0.25
Find the wrong number in the given number series.
2160, 360, 72, 18, 6, 2
3,10,27,4,16,64,5,25,125
- Find the wrong number in the given number series.
7, 16, 34, 70, 144, 290 In each of the following number series, one term is wrong. Find the wrong term.
4, 7, 12, 21, 28, 39, 52
In each of the following number series, one term is wrong. Find the wrong term.
3, 5, 8, 13, 21, 33, 55
88, 112, 78, 120, 64, 136
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