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    Question

    A delivery boy travels a certain distance from his

    warehouse to the customer’s house. At a speed of 15 km/h, he arrives 18 minutes late. But when riding at a speed of (30/6) meters per second, he gets there just 6 minutes late. What is the distance between the warehouse and the customer’s house?
    A 12 km Correct Answer Incorrect Answer
    B 10 km Correct Answer Incorrect Answer
    C 18 km Correct Answer Incorrect Answer
    D 32 km Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the distance be x km

    Time at 15 km/h: T1 = x/15 hours

    So, Speed = (30/6) × (18/5) = 18 km/h

    Now,

    T1 = x/15, T2 = x/18

    (x/15) - (x/18) = 12/60 = 1/5

    LCM of 15 and 18 is 90

    (6x - 5x)/90 = 1/5 → x/90 = 1/5

    So, x = 18 km

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