Question
A delivery boy travels a certain distance from his
warehouse to the customer’s house. At a speed of 15 km/h, he arrives 18 minutes late. But when riding at a speed of (30/6) meters per second, he gets there just 6 minutes late. What is the distance between the warehouse and the customer’s house?Solution
ATQ,
Let the distance be x km
Time at 15 km/h: T1 = x/15 hours
So, Speed = (30/6) × (18/5) = 18 km/h
Now,
T1 = x/15, T2 = x/18
(x/15) - (x/18) = 12/60 = 1/5
LCM of 15 and 18 is 90
(6x - 5x)/90 = 1/5 → x/90 = 1/5
So, x = 18 km
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