Question
Present ages of ‘A’, ‘B’ and ‘C’ are in the
ratio 4:7:12, respectively. If present average age of ‘A’ and ‘C’ is 32 years, then find the age of ‘B’ when ‘C’ was 30 years old?Solution
Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘4x’ years, ‘7x’ years and ‘12x’ years, respectively. ATQ; (12x + 4x) ÷ 2 = 32 Or, 16x = 64 So, x = 4 So, present age of ‘C’ = 12 × 4 = 48 years Present age of ‘B’ = 7 × 4 = 28 years Difference between the ages of ‘B’ and ‘C’ = 48 – 28 = 20 years So, age of ‘B’ when ‘C’ was 30 years old = 30 – 20 = 10 years
Find the wrong number in the given number series.
8, 16, 24, 32, 32, 64
121Â Â Â Â Â 127Â Â Â Â Â Â 133Â Â Â Â Â Â 142Â Â Â Â Â Â 160Â Â Â Â Â Â 206
...Find the wrong number in given number series.
6490, 6377, 6294, 6211, 6138
11Â Â Â Â Â 29Â Â Â Â Â Â 45Â Â Â Â Â 59 Â Â Â Â Â Â 70 Â Â Â Â Â Â Â 81
...Find the wrong number in given number series.
2482, 2507, 2607, 2842, 3232, 3857
96, 480, 120, 360, 150, 750
4, 5, 12, 39, 160, 806
 7    12     33    126    635  Â
Find the wrong number in the given number series.
2, 3, 5, 7, 11, 13, 17, 2011, 1341, 3070, 5267, 8011, 11386