Question
Suresh earned an interest of Rs. 903 on principal amount
of Rs. 2800 at some rate of compound interest in 2 years. How much more/less interest would he have earned on Rs. 3200 at the same rate of simple interest for the same duration?Solution
Let, rate of interest be ‘r’% per annum So, 903 = 2800 × {(1 + r/100)2 – 1} 129/400 = {(1 + r/100)2 – 1} 529/400 = (1 + r/100)2 (23/20)2 = (1 + r/100)2 23/20 = 1 + r/100 3/20 = r/100, r = 15 So, simple interest earned = 3200 × 0.15 × 2 = Rs. 960 Required amount = 960 – 903 = Rs. 57
More ESIC Part B Questions
What will come in the place of question mark (?) in the given expression?Â
70 % of 640 + 75 % of 360 - 19 × 12 = ?
(165 × 12) ÷ 45 + 110 = ? × 2
(75 + 0.25 × 10) × 4 = ?2 - 14
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
(? × 3)2 - 85 = 115 × 5 + 69
Simplify: 6(x³ − 2x² + 3x) − (x³ + 2x − 3).
1299.999 ÷ 325.018 × 24.996 = ?
(122 - 82 ) of 52 + 52 = ?2Â
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