New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer –

    If diameter of a circle is increased by 25%,

    what will be the area of the circle? I. Circumference of the circle is 88 m. II. Area of the circle is 616 sq.m.
    A If the data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question. Correct Answer Incorrect Answer
    B If the data in statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question. Correct Answer Incorrect Answer
    C If the data either in statement I alone or in statement II alone is sufficient to answer the question Correct Answer Incorrect Answer
    D If the data in both statements I and II together are necessary to answer the question. Correct Answer Incorrect Answer

    Solution

    From I, 2`Pi` r = 88m ⟹ r = `(88 x 7)/(22 x 2)` [if gte msEquation 12]> 88 x 7 22 x 2 [if !msEquation]-->[endif]-->= 14 m. [if gte msEquation 12]>∴d= [if !msEquation]-->[endif]-->d =28 m. [if gte msEquation 12]>∴ [if !msEquation]-->[endif]-->increased d = 125% of 28 = 35 m [if gte msEquation 12]>∴ [if !msEquation]-->[endif]-->increased r = 17.5 m [if gte msEquation 12]>∴ [if !msEquation]-->[endif]-->increased area =`Pi` [if gte msEquation 12]>π [if !msEquation]-->[endif]-->r² = `(22 x 17.5 x 17.5)/(7)` [if gte msEquation 12]> 22 x 17.5 x 17.5 7 [if !msEquation]-->[endif]-->= 962.5m² From II, [if gte msEquation 12]>π [if !msEquation]-->[endif]-->`Pi` r² = 616 m² ⟹ r²= `(616 x 7)/(22)` [if gte msEquation 12]> 616 x 7 22 [if !msEquation]-->[endif]-->= 196 [if gte msEquation 12]>∴ [if !msEquation]-->[endif]-->r = 14 m. [if gte msEquation 12]>∴d= [if !msEquation]-->[endif]-->d = 28 m. increased d = 125% of 28 = 35 m increased r = 17.5 m increased area = `Pi` r²= `(22 x 17.5 x 17.5)/(7)` = 962.5m²

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