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    Question

    If diameter of a circle is increased by 25%,

    what will be the area of the circle? I. Circumference of the circle is 88 m. II. Area of the circle is 616 sq.m. Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer –
    A If the data in statement I alone is sufficient to answer the question, while the data in statement II alone is not sufficient to answer the question. Correct Answer Incorrect Answer
    B If the data in statement II alone is sufficient to answer the question, while the data in statement I alone is not sufficient to answer the question. Correct Answer Incorrect Answer
    C If the data either in statement I alone or in statement II alone is sufficient to answer the question Correct Answer Incorrect Answer
    D If the data in both statements I and II together are necessary to answer the question. Correct Answer Incorrect Answer

    Solution

    From I, 2`Pi` r = 88m ⟹ r = `(88 x 7)/(22 x 2)` [if gte msEquation 12]> 88 x 7 22 x 2 [if !msEquation]-->[endif]--> = 14 m. [if gte msEquation 12]>∴d= [if !msEquation]-->[endif]--> d =28 m. [if gte msEquation 12]>∴ [if !msEquation]-->[endif]--> increased d = 125% of 28 = 35 m [if gte msEquation 12]>∴ [if !msEquation]-->[endif]--> increased r = 17.5 m [if gte msEquation 12]>∴ [if !msEquation]-->[endif]--> increased area =`Pi` [if gte msEquation 12]>Ï€ [if !msEquation]-->[endif]-->r² = `(22 x 17.5 x 17.5)/(7)` [if gte msEquation 12]> 22 x 17.5 x 17.5 7 [if !msEquation]-->[endif]--> = 962.5m² From II, [if gte msEquation 12]>Ï€ [if !msEquation]-->[endif]-->`Pi` r² = 616 m² ⟹ r²= `(616 x 7)/(22)` [if gte msEquation 12]> 616 x 7 22 [if !msEquation]-->[endif]--> = 196 [if gte msEquation 12]>∴ [if !msEquation]-->[endif]--> r = 14 m. [if gte msEquation 12]>∴d= [if !msEquation]-->[endif]-->d = 28 m. increased d = 125% of 28 = 35 m increased r = 17.5 m increased area = `Pi` r²= `(22 x 17.5 x 17.5)/(7)` = 962.5m²

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