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Some tubes are wires (I) + No wire is a lamp (E) ⇒ Some tubes are not lamps (O) Some bulbs are tubes (I) ⇒ Conversion ⇒ Some tubes are bulbs (I) ⇒ [Probable conclusion] ⇒ Some tubes may not be bulbs (O). Some tubes are wires (I) ⇒ Conversion ⇒ Some wires are tubes (I) ⇒ [Probable conclusion] ⇒ All wires may be tubes (A) Hence, option 2 is correct. By elimination method - By 1 and 4, no possibility case can be drawn between tube and bulb. Hence both are eliminated. By 3, no + no = no relation can be drawn between tubes and lamps. Hence it is eliminated. Hence answer is option 2.
Which is the lead agency for implementing e-NAM?
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Generally for destruction of Clostridium botulinum,________ process is done
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The type of germination observed in pigeon pea?
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