Question
In the given question, three conclusions are given and
five statements as 1), 2), 3), 4) and 5). You need to choose the option that contains the set of statements from which the given conclusions logically follow. Conclusions: Some raisins being cashew is a possibility. Some almonds are dates. All cashews being raisins is a possibility.Solution
All cashews are dates (A) + Some dates are raisins (I) ⇒ Probable conclusion ⇒ Some cashews may be raisins (I). Some dates are raisins (I) + All raisins are almonds (A) ⇒ Some dates are almonds (I) ⇒ conversion ⇒ Some almonds are dates (I). All cashews are dates (A) + Some dates are raisins (I) ⇒ Probable conclusion ⇒ Some cashews are raisins (I) ⇒ Probable conclusion ⇒ All cashews may be raisins (I).
The LCM for two prime numbers x and y, (x > y) is 319. The value of (2y + x) :
- The product of two numbers is 4620 and their L.C.M is 210. What is the H.C.F of the two numbers?
What is the HCF of 4/5, 6/8, 8/25 ?
The greatest number of four digits which when divided by 6, 8, 10 leave remainders 3, 5, 7 respectively is:
- The product of two numbers is 5600 and their L.C.M is 280. What is the H.C.F of the two numbers?
Let N be the greatest number that will divide 86, 112, 138 leaving the same remainder in each case. Then sum of the digits in N is:
The LCM of the two numbers is 12 times their HCF. The sum of LCM and HCF is 429 and if both the number are smaller than their LCM. Find both numbers.
- The product of two numbers is 2160 and their L.C.M is 180. What is the H.C.F of the two numbers?
The product of two numbers is 3600 and their GCD is 30. What is the LCM?
Find the highest common factor (HCF) of (15/4) , (10/9) and (25/6)
