Question
Conclusions: I. Some Years are being Months is a
possibility II. Some Weeks are being Years is a possibility Statements: In the question below some statements are given two conclusions followed by some statements. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read the conclusions and then decide which of the following statement is true for given conclusions.Solution
Only a few Months are Days (I) + No Day is Year (E) → Some Months are not Years (O) → Probable conclusion → Some Years may be Months (I). All Days are Weeks (A) → Conversion → Some Weeks are Days (I) + No Day is Year (E) → Some Weeks are not Years (O)  → Probable conclusion → Some Weeks may be Years (I).Â
- The cost of item A is 8 more than the sum of cost of B and C together. The ratio of cost of item B and C is 3:5 respectively. The cost of B is a multiple o...
4096Â Â Â Â Â Â Â Â 2048Â Â Â Â Â 514Â Â Â Â Â 64Â Â Â Â Â Â Â Â Â Â 4
...When a number is divided by 17, the remainder remains 6. Find the remainder obtained when the square of the same number is divided by 17.
Find the remainder when (5)100 is divided by 7
Which number from the following is divisible by 24?
A) 825196
B) 674328
C) 592416
D) 431232Â If the sum of two numbers is 33 and their difference is 15, the smaller number is
The value of
- The sum of two numbers is 90 whereas the sum of their reciprocals is (30/11). Find the square of the product of the two numbers.
- Determine the maximum digit that can replace 'k' in 'k75381' so that it becomes divisible by 3.
Find the highest common divisor of 1080, 2700, and 6480.