Question
In the question below some statements are given followed
by three conclusions I, II and III. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of the given conclusion definitely follows from the given statements, disregarding commonly known facts. Statements: Some Surprises are Gifts. All Gifts are Boxes. No Box is Empty. Conclusions: I. Some Gifts are Box. II. Some Surprises are Empty. III. No Empty is Gift.Solution
All Gifts are Box (A) →I.I. → Some Gifts are Boxes (I). Hence conclusion I follows.
Some Surprises are Gifts (I) + All Gifts are Boxes (A) → Some Surprises are Boxes (I) + No Box is Empty (E) → Some Surprises are not Empty (O). Hence conclusion II does not follows.
All Gifts are Boxes (A) + No Box is Empty (E) → No Gifts is Empty (E) → Conversion → No Empty is Gifts (E). Hence conclusion III follows.
54.97% of 620.08 + 16.13 × 11.11 – 829.91 ÷ 5 = ?
123% of 3825 +2745 =11800 - ?
...? × 32.91 – 847.95 ÷ √16.4 – 13.982 = √24.7 × 24.04
(699.88% of 32) + (80.44% of 400.23) = ? + (11.67)2
56.02% of 1499.98 + 64.04% of 2501.01 = ? + 25.05 × 49.98 + 6.063
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....
? = 200.24 + 1077.97 – 14.992
(8.013 – 25.04) = ? + 11.98% of 2399.98
7/12 of 539.98 – 23.98 × 9.03 + 77.89 = ?
