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No eraser is ink(E) + Some inks are pencil(I) ⇒ Some pencil are not erasers(I). Hence conclusion I follows but conclusion III does not follow. Some pens are sharpeners(I) + All sharpeners are erasers (A) ⇒ Some pens are erasers(I) ⇒ Probable Conclusion ⇒ All pens being eraser is a possibility(A). Hence conclusion II follows. Alternate Method: