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W’s brother S, sits on the immediate left of his mother who has 6 coins. P is the father of V and only one person sits between W’s mother and T. U, who is sister of V, has 7 coins and is not an immediate neighbour of W’s husband. V is father of R and is not an immediate neighbour of T. P is married to W. By the statement ‘only one person sits between W’s mother and T’, we find that Q is W’s mother and T is S’ daughter. No female is an immediate neighbour of Q, who sits at the corner of the table. Q sits second to the left of W’s husband who has neither 4 nor 7 coins. Only one person is sitting between P and U. S’s daughter sits second to the right of U and on the immediate left of that person who has 3 coins. T sits on the immediate right of the person who has 2 coins.
S, sits on the immediate left of his mother who has 6 coins. V is not an immediate neighbour of T. So, V can sit at immediate right or immediate left to P. If V sits immediate right to P, and as we know that W is female so she sit at immediate left to T. We know that V sits second to the right of the person who has 8 coins. By this statement this condition is not possible. If V sits immediate left to P, so W will sit at immediate right to P. Then R will sit at immediate left to T. Further V sits second to the right of the person who has 8 coins. It is given that T has 1 coin and that of U is 7. So V will have 4 and P will have 5 coins
Statements:Q = S > T > Z; T > Y = H < I
Conclusions: I. Z > H II. I > Z
Statement:
O ≤ P > K ≤ L; W ≤ X = K > R; Q > L
Conclusion:
I. O > K
II. L < P
Statements: A > C = E > G, G > J ≥ L = N
Conclusion:
I. A > L
II. A ≥ N
Statements:
A ≤ B < C > K; C < S > T; T < U < V
Conclusions:
I). A < S
II). A ≥ S
...Statements: B > A = D ≥ C = I ≥ H > E > F > G
Conclusions:
I. C ≥ E
II. E > C
III. A ≥ D
Statements: S > V = T, U < X < T, W > U
Conclusions:
I. W > T
II. V > U
III. S > X
Statement: B = E ≥ F ≥ M < J < V ≥ R; M > A
Conclusion:
I. A ≥ R
II. B > A
...Statements:
P < Q < R < S ≤ B < H; S > N ≥ Y
Conclusions:
I) P < Y
II) R ≥ N
Statements: O > P ≥ Q; N ≤ M < R; O = M ≤ S
Conclusions:
I. N < O
II. R > P
III. Q < M
Statement:
J < K ≤ M > O; M > P < Z; Z = R
Conclusion:
I. P < K
II. R > K