Question
An investment becomes 175% of the principal in 60 months at
simple interest rate of ‘r%’ p.a. Find the rate of interest ‘r’.Solution
ATQ,
Let the principal be Rs. ‘P’.
ATQ,
1.75P – P = (P × 60 × r)/(12 × 100)
Or, 0.75P = Pr/20
Or, r = 15.
?2/3 = 33.33% of 107.99 + 45.45
(752.09 - 43.04 x 7.94) ÷ 16.9 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
41.98% of 2200.031 + 15% of 3999.9 = ?
Find the approximate value of Question mark(?). No need to find the exact value.
71.92 ÷ 8.02 × 6 + 44.95% of 499.79 – √(80.91) – 10.03...
11.11% of (123.45 + 234.56) + 10.01³ - (5.05 of 7.07) = ? of (88.88 - 33.33)
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
2720.03 ÷ 79.98 x 39.9 = ? + 40.32
3245.69 + ? – 3112.48 = 2654.87 – 2412.92
20.02% of (95.96 × 104.01 – 56.02 × 64.04) – ? = 12.02 × 39.96 + 103.03