Question
Car A departs from Varanasi towards Lucknow at 8:00 AM,
traveling at a speed of 48 km/h. Car B starts from Lucknow towards Varanasi at 9:15 AM, with a speed that is 25% greater than Car A's speed. If the distance between Varanasi and Lucknow is 1140 km, at what distance from Varanasi will the two cars meet?Solution
Speed of cars A = 48 kmph Speed of cars B = 48 * 125/100 = 60 kmph After one hour and 15 minutes cars A covers the distance = 48 + 48/4 = 60 km Time taken by two cars meet each other = (1140 – 60)/(60 + 48) = 10 hours Required distance = 10 * 48 + 60 = 480 + 60 = 540 km
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
The base of a prism is an equilateral triangle with a perimeter of 36 cm. If the height of the prism is 12 cm, calculate the volu...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
22.11 × 4.98 + 23.03 × 5.12 – 32.95 + 96.9 × 5.02 =?
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
√440.98 + (17.95% of 249.96 – 12% of 99.99) + (7.12)2 = ?
What approximate value will replace the question mark (?) in the following?
√36...
19.22 × 11.99 + 142.15 = ?
?% of 399.99 + 139.99 ÷ 6.99 = 59.99% of 559.99 + 41.09 X 15.99
99.99% of 9.99 + 299.98% of 129.98 = ?2
