Question
If ‘742x319’ is a seven-digit number that is exactly
divisible by 72, then what is the digit ‘x’?Solution
ATQ,
A number divisible by 72 must be divisible by both 8 and 9.
To be divisible by 9, the sum of digits must be divisible by 9.
Sum of digits = 7 + 4 + 2 + x + 3 + 1 + 9 = (26 + x)
We need 26 + x to be divisible by 9.
Trying values:
26 + x = 27 → divisible by 9
⇒ x = 1
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