Question
In a tank, the ratio of petrol to kerosene is 7:5. 50% of this mixture is removed and replaced with kerosene. Again, 50% is replaced with petrol. Find the final ratio of petrol to kerosene in the tank.
Solution
ATQ,
Petrol = 7x, Kerosene = 5x → Total = 12x litres
First step (50% replaced with kerosene):
Petrol = 0.5 × 7x = 3.5x litres
Kerosene = 0.5 × 5x + 0.5 × 12x = 2.5x + 6x = 8.5x litres
Second step (50% replaced with petrol):
Petrol = 0.5 × 3.5x + 0.5 × 12x = 1.75x + 6x = 7.75x litres
Kerosene = 0.5 × 8.5x = 4.25x litres
Final ratio = 7.75x : 4.25x = 775 : 425 = 31:17
More Reasoning Miscellaneous Questions
- An email account that is accessed through a Web browser& emails are typically not downloaded to the user's computer but stored on the Web-based email s...
- Find the fraction which is greater than (5/7) but less than (9/7).
- OCR stands for:
- Ravi invested Rs. 25,000 for 2 years at a compound interest rate of 20% per annum, compounded annually. What will be the total amount he will get after 2 y...
- A trader purchases a product for Rs. 250 and earns a profit of 45%. Calculate the selling price of the product.
- Simplify:- 100 ÷10-[-2+{-9+(3-6 of 2)}]=.
- How many seats are there around the table?
- What is the possible weight of R?
- Statement: I: The fare of public transport dropped marginally last week. II: The state government reduced the tax on public transport last week.
- The average height of each person in group 'E' having 40 people is 15 cm less than the average height of each person in group 'F' having 35 people. If the ...
Relevant for Exams:
