Question
In a tank, the ratio of petrol to kerosene is 7:5. 50% of
this mixture is removed and replaced with kerosene. Again, 50% is replaced with petrol. Find the final ratio of petrol to kerosene in the tank.Solution
ATQ,
Petrol = 7x, Kerosene = 5x → Total = 12x litres
First step (50% replaced with kerosene):
Petrol = 0.5 × 7x = 3.5x litres
Kerosene = 0.5 × 5x + 0.5 × 12x = 2.5x + 6x = 8.5x litres
Second step (50% replaced with petrol):
Petrol = 0.5 × 3.5x + 0.5 × 12x = 1.75x + 6x = 7.75x litres
Kerosene = 0.5 × 8.5x = 4.25x litres
Final ratio = 7.75x : 4.25x = 775 : 425 = 31:17
64.64% of 419.89 + 116.61 = ? x 12.89
999.99 + 99.99 + 99= ?
(? + 11.86) X 14.89 = 19.89% of 2399.89
? = 21.91% of (36.2 × (144.01 + 5.95)) + 16.71
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
499.98% of (√440.8 + 12.922 ) - 12.02 of 4.82 = ? of 9.82 + 9.98% of 999.94
92% of 1650 + 32² = ? + 1504 ÷ 16
44.89% of 600.25 + (29.98 × 5.67) + (√1940 – 10.29) = ?2
What will be the approximate value of the following questions.
(74.75% of 600.29 – 44.85% of 399.99) × (√224.95 ÷ 15.01) = ?
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