Question
Answer the following questions based on the
information given below. Seven persons T, U, V, W, X, Y and Z has different weights. T is heavier than at least two persons. X is heavier than V, who is not the lightest. X is lighter than at least three persons. Z is heavier than W, is heavier T. U is heavier than at least five persons. U is not the heaviest. Who among the following is third heaviest?Solution
U is heavier than at least five persons. U is not the heaviest. ____> U > ____ > ____ > ____ > ____ > ____ X is lighter than at least three persons. ____> U > ____ > X > ____ > ____ > ____ ……. (I) ____> U > ____ > ____ > X > ____ > ____ ……. (II) X is heavier than V, who is not the lightest. T is heavier than at least two persons. Z is heavier than W, is heavier T. Case 2 will get discarded as we cannot place T. Z > U > W > X / T > T/X > V > Y ……. (I) Z > U > ____ > ____ > X > V > ____ ……. (II) Therefore, the final arrangement is as follow: Z (heaviest) > U > W > T/X> X/T > V > Y (lightest)
How many elements are there between ‘03’ and ‘45’ in step-II?
If the entry code for Batch A on Thursday (4th May,2017) was “camera affixes to the hands knuckles that takes in”, then which of the fol...
Statements: D @ M, M % I, I # C, C $ F
Conclusions : I. C % M II. D @ I III. F @ I
...Which step would be the following output?
Tall 50 person 42 hope 32 equal 26 centre 22 75 wave
Which of the following would be the last step of the rearrangement?
Following is the step III for an input. What will be the first step for the input?
Step III: 12, 315, 48, 223, 142, 419, 567
What is the sum of all the elements of step V?
The entry codes for which of the following batches of Tuesday will not change on Thursday?
If step IV of an input is ‘the knee joint of animal to see remains’, what is the step III of that input?
. If an input is ‘In spite of the increase green house gas’, what is the step III of that input?