Question
The population of a city increases by 18% every year. If
the population after 2 years will be 41,472, what is the present population?Solution
ATQ,
Let, the present population be βxβ.
ATQ,
So, the population after 2 years = 1.18 Γ 1.18 Γ x = 41472
Or, x = 41472 Γ (1/1.18) Γ (1/1.18)
So, x = 29,800
Therefore, present population of the city = x = 29,800
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