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    Question

    Eight persons D, E, F, G, H, I, J and K standing in a

    queue according to their height. D is fourth tallest person. J is taller than D. J is two persons taller than K. G is taller than both E and H. F is taller than G. H is two persons shorter than I. The number of persons taller than I is more than the number of shorter than G. How many persons are shorter than F?
    A Seven Correct Answer Incorrect Answer
    B Six Correct Answer Incorrect Answer
    C Five Correct Answer Incorrect Answer
    D Cannot be determined Correct Answer Incorrect Answer
    E Four Correct Answer Incorrect Answer

    Solution

    D is fourth tallest person. J is taller than D. J is two persons taller than K. J  >  _____ > K > D >  _____ > ______ >  _____ > _____  ….. (I) _____  >  _____ > J > D >  K > ______ >  _____ > _____  ….. (I)   G is taller than both E and H. F is taller than G.  H is two persons shorter than I. The number of persons taller than I is more than the number of shorter than G. Case 2 will get discarded. J  >  F > K > D >  G > I  >  E > H  ….. (I) _____  >  _____ > J > D >  K > I >  _____ > H  ….. (I) Therefore, the final arrangement is as follow: J(Tallest) > F > K > D > G > I > E > H(Shortest) Six persons are shorter than F.

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