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Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘8x’ years, ‘9x’ years and ‘12x’ years, respectively. ATQ; (12x + 8x) ÷ 2 = 20 Or, 20x = 40 So, x = 2 So, present age of ‘C’ = 12 × 2 = 24 years Present age of ‘B’ = 9 × 2 = 18 years Difference between the ages of ‘B’ and ‘C’ = 24 – 18 = 6 years So, age of ‘B’ when ‘C’ was 20 years old = 20 – 6 = 14 years
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