T, R and S entered into a business together for 2 years. T invests twice the amount Funded by R. R invests 2000 more than S. Out of the total profit of 10800. R gets 3000 as a gain. Find the amount Funded by T.
Let the initial investment done by S is taken as (x) T R S (2x + 2000) (x + 2000) (x) (x + 2000) / (4x + 6000) = 3000/10800 18x + 36000 = 20x - 18x 36000 - 30000 = 20x - 18x 2x = 6000 x = 3000 then, the initial Funding done by T will be :- 2x + 4000 = 2 x 3000 + 4000 = Rs 10000
I. 14p² + 9p - 8 = 0
II. 4q² - 19q + 12 = 0
I.12a2– 55a + 63 = 0
II. 8b2- 50b + 77 = 0
...I. 2x2– 5x – 12 = 0
II. 2y2+ 13y + 20 = 0
I. 6x2- 47x + 77 =0
II. 6y2- 35y + 49 = 0
A and B are the roots of equation x2 - 13x + k = 0. If A - B = 5, what is the value of k?
I. 17x² - 26x – 16 = 0
II. 17y²- 26y + 9 = 0
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
I. 2y2+ 13y + 15 = 0
II. 2x2+ 11 x + 12 = 0
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
