Question
T, R and S entered into a business together for 2 years.
T invests twice the amount Funded by R. R invests 2000 more than S. Out of the total profit of 10800. R gets 3000 as a gain. Find the amount Funded by T.Solution
Let the initial investment done by S is taken as (x) T             R           S     (2x + 2000)   (x + 2000)     (x) (x + 2000) / (4x + 6000) = 3000/10800 18x + 36000 = 20x - 18x 36000 - 30000 = 20x - 18x 2x = 6000 x = 3000 then, the initial Funding done by T will be :- 2x + 4000 = 2 x 3000 + 4000 = Rs 10000
What will come in place of the question mark (?) in the following series?
23, 46, ?, 184, 368, 736
If √n + (1/√n) = 6, then find the value of n + (1/n).
If 9 : 12 :: 12: x, and 28: 42:: 42: y, then the value of 2x + y is:Â
In ∆ ABC, MN ‖ BC, the area of quadrilateral MBCN=130 sqcm. If AN : NC = 4 : 5, then the area of ∆ MAN is:
If
= -2 then find If a = 2 + √3, then the value of (a6 + a4 + a2 + 1)/a3 is
If n = 6 + √13, then find the value of (n + 1/n)².
Relevant for Exams:
