Question
Present ages of βAβ, βBβ and βCβ are in the
ratio 7:5:8, respectively. If present average age of βAβ and βCβ is 30 years, then find the age of βBβ when βCβ was 26 years old?Solution
Let the present ages of βAβ, βBβ and βCβ be β7xβ years, β5xβ years and β8xβ years, respectively. ATQ; (8x + 7x) Γ· 2 = 30 Or, 15x = 60 So, x = 4 So, present age of βCβ = 8 Γ 4 = 32 years Present age of βBβ = 5 Γ 4 = 32 years Difference between the ages of βBβ and βCβ = 32 β 20 = 12 years So, age of βBβ when βCβ was 26 years old = 26 β 12 = 14 years
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