Question
Present ages of βAβ, βBβ and βCβ are in the
ratio 7:5:8, respectively. If present average age of βAβ and βCβ is 30 years, then find the age of βBβ when βCβ was 26 years old?Solution
Let the present ages of βAβ, βBβ and βCβ be β7xβ years, β5xβ years and β8xβ years, respectively. ATQ; (8x + 7x) Γ· 2 = 30 Or, 15x = 60 So, x = 4 So, present age of βCβ = 8 Γ 4 = 32 years Present age of βBβ = 5 Γ 4 = 32 years Difference between the ages of βBβ and βCβ = 32 β 20 = 12 years So, age of βBβ when βCβ was 26 years old = 26 β 12 = 14 years
From the given answer figures, select the one in which the question figure is hidden / embedded(rotation is not allowed).
Select the answer figure in which the question figure is hidden ?
Find out the alternative figure which contains figure (X) as its part.
Select the option that is embedded in the given figure.
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
From the given answer figures, select the one in which the question figures is hidden.

In each of the following questions, you are given a figure (X) followed by four alternative figures (1), (2), (3) and (4) such that figure (X) is embed...
Select the option figure which is embedded in the given figure. (Rotation is not allowed).
