Question
Present ages of ‘A’, ‘B’ and ‘C’ are in the
ratio 5:11:13, respectively. If present average age of ‘A’ and ‘C’ is 36 years, then find the age of ‘B’ when ‘C’ was 27 years old?Solution
Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘5x’ years, ‘11x’ years and ‘13x’ years, respectively. ATQ; (13x + 5x) ÷ 2 = 36 Or, 18x = 72 So, x = 4 So, present age of ‘C’ = 13 × 4 = 52 years Present age of ‘B’ = 11 × 4 = 44 years Difference between the ages of ‘B’ and ‘C’ = 52 – 44 = 8 years So, age of ‘B’ when ‘C’ was 27 years old = 27 – 8 = 19 years
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2
15% of 1800 + 22 = ?
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