Question
If marks of F is 80 and sum of marks of F and G is 130,
then what may be the possible marks of I? Answer the questions based on the information given below. Six persons - D, E, F, G, H, I are ranked according to their marks. The marks of E is more than the marks of H. The number of persons more than E is one less than the number of persons less than H. The marks of F is more than I, whose marks is more than G. At least two persons have less marks than G.Solution
F + G = 120 80 + G = 130 G = 130 – 80 = 50. Possible Marks of I will between 50 and 80. The marks of E is more than the marks of H. The number of persons more than E is one less than the number of persons less than H. E > ___ > _____ > ___ H > ___ ……… (I) ____ > E > ___ > H > ___ > ___ ……… (II) The marks of F is more than I, whose marks is more than G. At least two persons have less marks than G. E > F > I > G > H > D ……… (I) ____ > E > ___ > H > ___ > ___ ……… (II) Case 2 will get discarded. Therefore, the final arrangement is as follow: E(highest) > F > I > G > H > D(lowest)
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