Six persons H, X, E, J, L and K stand in a queue

Solution

Not more than two persons are shorter than K. ___  > ____ > _____ K > ___  > ____ ………. (I) ___  > ____ > _____ > ____ > K > ____ …….. (II) ___  > ____ > _____ > ____ > ____ > K …….(III) L is taller than E, who is taller than K. H is taller than both X and J, who is not shortest. H is shorter than E. J is not third shortest person. L  > E > H > K > J  > X ………. (I) L  > E > H > J > K > X…….. (II) L  > E > H > X > J > K …….(III) The final arrangement is as follow: Case 1: When K is the third shortest person. L > E > H > K > J > X Case 2: When K is the shortest person. L > E > H > X > J > K So, four persons are taller than J.