Question
How many items are heavier than the item
R? Answer the questions based on the information given below. There are six items P, Q, R, S, T and U. Each of the items has different weight. P is heavier than S but lighter than U. The weight of second heaviest item is 58kg. The weight of the second lightest item is 35kg. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P.Solution
P is heavier than S but lighter than U. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P. U > P > S Or Q > S > T Also, T is the lightest among all and U is not the heaviest. So, Q must be the heaviest item among all. The final arrangement is as follows: Q > U(58) > P > S/R > R/S (35) > T
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
79.99% of (84.89 × 5.99) - (3.89)2 × 21.87 = ?
(29.892 × √290) + 32.98 × 6.91 = ?
44.84% of 799.94 + (625.21 ÷ 24.91) – √(224.77) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
[54.96 × √99.96 – {(25.02/6.84)% of 280.24}]/(3.032 × 19.87) = ?
Relevant for Exams:
