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K lives on the top floor. F is in the middle of the North facing people’s row. G lives on the 3rdfloor. There are exactly three floors between K and I. H and E sit at the extreme ends of the row and face south.
C sits to the left of H. This is not possible in Case II, therefore, Case II will be eliminated.
J and C sit opposite to each other. The person living on the 5thfloor (i.e. I) sits opposite to H and faces north. lives above C’s floor J does not live on 8thor 7thfloor. J cannot be on 6th or 4th floor also as C lives immediately below J. (so, J lives on 2nd floor and C on 1st floor), D sits third to the right of J.
D does not sit adjacent to vacant place. (Therefore, vacant place is in the south facing row.) G faces south. K faces the vacant place. The persons at the extreme ends of the north facing row are immediately next to each other’s floor (i.e. I and D). G is not immediately next to D’s floor.
H and E are immediately next to each other’s floor. Case-1
The mode of the sample data = is 24 and the median = 80. Find the mean of this distribution
21 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 179. Find the smallest part.
The median of the following data will be ___
32,25,33,27,35,29,14,26 and 30.
What will be the 11th term of the arithmetic progression 3, 8, 13, _____?
The sum of the first 10 terms of an arithmetic sequence is 60 and the 10th term is 5. What is the first term of the sequence?