Question
How many boxes are placed below box
X? Study the following information carefully to answer the given questions: A certain number of boxes are placed one above the another in three different columns I, II and III, in such a way that Column II is in east of column I and in west of Column III. There are not more than six boxes in any of the column. In column III number of boxes are more than column II but less than column I. Box N is placed immediately above box A. There are two boxes placed between box G and box H, which is placed below the box G in the same column. Box J is placed to the immediate east of box X. Only one box is placed between box N and box E in the same column. Box K is placed immediately below box F. Box B is not placed in same column with box E. Box D is not placed at bottom of any of the column. The total number of boxes is multiple of 5. Only one box is placed between box I and M in column II. Box C is placed immediately below box I. Box L is placed in the west of box C. Only one box is placed between box L and box G in the same column. Only one box is placed between box J and box A in the same column.ΒSolution
Only one box is placed between box I and M in column II. Box C is placed immediately below box I. Box L is placed in the west of box C. Only one box is placed between box L and box G in the same column. From these conditions we have three possible cases.
There are two boxes placed between box G and box H, which is placed below the box G in the same column. By this condition case- 2 and case- 3 are cancelled. Box J is placed to the immediate east of box X. Only one box is placed between box J and box A in the same column. Box N is placed immediately above box A. By these conditions one more case added in case- 1. So new arrangement will be β
Only one box is placed between box N and box E in the same column. Box K is placed immediately below box F. By this condition case- 1a is cancelled. Box B is not placed in same column with box E. Box D is not placed at bottom of any of the column. So final arrangement will be-Β Β Β 
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