Question
Mohit walked 30 metres towards South. Then he turned to
his left and walked 25 metres. He then turned to his left and walked 30 metres. He again turned to his right and walked 10 metres. At what distance is he from the starting point in which direction? Â Study the following information carefully and answer the questions below-:Solution
Mohit ‘s distance from starting point A = AE = (AD + DE) = (BC + DE) = (25 + 10) m = 35 m. E is to the East of A.Â
I. 3x2 = 2x2 + 9x – 20
II. 3y2 = 75
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 92x + 73 = 0
Equation 2: 17y² - 76y + 59 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer Â
I. 3x² –7x + 4 = 0�...
I. x2 – 7x + 12 = 0
II. y2 – 7y + 10 = 0
I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. 2x² - 7x + 3 = 0
II. 8y² - 14y + 5 = 0
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
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