The question below can be answered using the sentence given in only one of the options. Find out the option which can be used to answer the question.

Eight persons S, T, U, V, W, X, Y and Z have different height but not necessarily in the same order. How many persons are taller than U?

Solution

From option [1], Only three persons are shorter than Z. Two persons have height between Z and U. As many persons are shorter than U as taller than T. Two persons have height between T and S. Y is just taller than S. Case 1: When U is taller than Z. __ > U > Y > S > Z > __ > T > __ Case 2: When U is shorter than Z. T > __ > Y > S > Z > __ > __ > U Either one or seven persons are taller than U. So, data given in option [1] is not sufficient to answer the given question. From option [2], As many persons are taller than W as shorter than V. U is taller than Z, who is just taller than X. T is the second shortest person. V is shorter than T. Y is taller than S, who is taller than Z. C is taller than S. W > Y/U > U/Y > S > Z > X > T > V Either one or two persons are taller than U. So, data given in option [2] is not sufficient to answer the given question. From option [3], Y is 3 rd tallest person. V is just shorter than T, who is shorter than S. U is taller than S, who is taller than Z. As many persons are taller than U as shorter than T. Z is taller than X W > U > Y > S > Z > X > T > V Only one person is taller than U. So, data given in option [3] is sufficient to answer the given question. From option [4], Only three persons have height between U and X. No one is taller than W. Y is taller than Z. X is taller than at most 2 persons. Y is taller than T. V is shorter than T. Number of persons taller than T is one more than the number of persons shorter than Y. No fix arrangement can be formed. So, data given in option [4] is not sufficient to answer the given question.