Question
If the sum of the weight of C and the third heaviest
person is 99kgs, then what may be the weight of F? Answer the questions based on the information given below. Seven box A, B, C, D, E, F and G have different weight but not necessarily in the same order. The difference between the weight of E and C is 30kgs. The weight of second heaviest box is 69kgs. Only one box is lighter than G. A is just heavier than F, which is heavier than C. Two boxes have weight between G and A. D is just heavier than E. C is not the lightest.Solution
The weight of second heaviest box is 59kgs. Only one box is lighter than G _____ > 69 > ____ > _____> _____> G > ____ A is just heavier than F, which is heavier than C. Two boxes have weight between G and A. D is just heavier than E. C is not the lightest person. D > E(69) > A > F > C > G > B The difference between the weight of E and C is 30kgs. E – C = 30 69 – C = 30 C = 69 – 30 = 39. So, C + A = 99 39 + A = 99 A = 99 – 39 = 60. F’s weight will be more than 39 but less than 60.
- Determine the largest common factor of 1764, 4410, and 8820.
22Â Â Â Â Â Â Â Â Â Â 44Â Â Â Â Â Â Â Â Â Â 176Â Â Â Â Â Â Â Â 1078Â Â Â Â Â Â 8448
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