If the sum of the weight of C and the third heaviest person is 99kgs, then what may be the weight of F?
The weight of second heaviest box is 59kgs. Only one box is lighter than G _____ > 69 > ____ > _____> _____> G > ____ A is just heavier than F, which is heavier than C. Two boxes have weight between G and A. D is just heavier than E. C is not the lightest person. D > E(69) > A > F > C > G > B The difference between the weight of E and C is 30kgs. E – C = 30 69 – C = 30 C = 69 – 30 = 39. So, C + A = 99 39 + A = 99 A = 99 – 39 = 60. F’s weight will be more than 39 but less than 60.
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