Directions: Study the following arrangement carefully and answer the question given below. A 7 G 4 M 9 R 2 T 6 K 8 P 3 D 5 H 1 L First, subtract 2 from the digits which are immediately preceded by a consonant and immediately followed by a consonant. Then, add 1 to the remaining digits. After performing the operation, remove all repeated digits. Now find the sum of all odd digits obtained.

Given arrangement: A 7 G 4 M 9 R 2 T 6 K 8 P 3 D 5 H 1 L Digits are:
7, 4, 9, 2, 6, 8, 3, 5, 1 Now check digits which are immediately preceded and followed by consonants. 4 is between G and M → subtract 2 → 2
9 is between M and R → subtract 2 → 7
2 is between R and T → subtract 2 → 0
6 is between T and K → subtract 2 → 4
8 is between K and P → subtract 2 → 6
3 is between P and D → subtract 2 → 1
5 is between D and H → subtract 2 → 3
1 is between H and L → subtract 2 → -1 7 is preceded by A and followed by G, so it does not satisfy the condition because A is a vowel.
So, add 1 to 7 → 8 Final digits: 8, 2, 7, 0, 4, 6, 1, 3, -1 Remove repeated digits: no repeated digit is present. Odd digits are: 7, 1, 3, -1 Sum = 7 + 1 + 3 - 1 = 10