Question
If in the number '6453146526', 2 is added to all the
digits, then what is the absolute difference between the sum of the digits which are repeated and the sum of the digits which are not repeated after rearrangement? Note: The repeated digits are to be considered only once while taking the sum. Â Â Â Â Â ÂSolution
6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6 8Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8 The digits which are repeated are '8', '6', and '7', so sum = (8 + 6 + 7) = 21. The digits which are not repeated are '5', '2', and '4', so sum = (5 + 2 + 4) = 11. Difference = (21 - 11) = 10.
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